New Delhi: India will have a small addition to their busy 2018 cricketing schedule after the BCCI announced a two-T20I tour to Ireland at the end of June.
The team will travel to Ireland to play two T20Is before they embark on their tour to England in July. The two matches will be held on 27th and 29th June 2018, in Dublin.
This is the first time the Men in Blue are making a trip to Ireland since 2007. The last time the side was there Ireland, they played an ODI at Belfast, winning the game by nine wickets via the Duckworth Lewis method.
Interestingly, it was Rohit Sharma's debut international game for India.
After the end of the IPL in May, India will squeeze in the Ireland tour before their visit to England for a 3-match T20I, 3-match ODI, and five-match Test series. It is also expected that some players will head to England before the others to get a feel of the conditions and play some County games.
The only time India faced off against Ireland in the game's shortest format was in the 2009 World T20 at Nottingham, where the Indians won by a comfortable margin of 8 wickets.